Key Question #3 - 1 mol = 4.97g 0.01838mol = 270.4 g/mol...

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Lesson 3 Key Questions 13) Molar mass of TiO 2 = 79.88 g/mol Molar mass of AgCl = 143.32 g/mol 1.2g / 79.88g/mol = 0.015 mol of Ti atoms 6.45g / 1443.32 = 0.045 mol of Cl atoms n= 0.045mol / 0.015mol n=3 The ratio of Ti to Cl is 1:3 The simplest formula of the original compound is TiCl 3 14) Moles of C = 80.0g / 12.0g/mol = 6.67 mol Moles of H = 8.2g / 1.01g/mol = 8.12 mol Moles of O = 11.8g / 16g/mol = 0.75 mol C = 6.67mol / 0.75mol = 9 H = 8.12mol / 0.75mol = 11 O = 0.75mol / 0.75mol = 1 The empirical formula C 9 H 11 O n=(PV)/(RT) n=(0.9atm x 0.793L) / (0.0821 kPa L x 473K) n=0.01838 mol 0.01838 mole of Estrone has a mass of 4.97g
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Unformatted text preview: 1 mol = 4.97g / 0.01838mol = 270.4 g/mol molar mass of C 9 H 11 O = 135.2 g/mol n= 270.4 g/mol / 135.2g/mol n=2 The molecular formula for Estrone is C 18 H 22 O 2 15) Ammonia = NH 3 Ammonium nitrate = NH 4 NO 3 Molar mass = 17 g/mol Molar mass = 80.1 g/mol % of N = 14.01 g/mol / 17g/mol % of N = 28g/mol / 80.1g/mol % of N = 82.9 % of N = 35% The liquid ammonia (NH 3 ) would be better because it has a higher concentration of Nitrogen by mass. The ammonia has 82.9% Nitrogen compare to 35% Nitrogen of the ammonium nitrate....
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This note was uploaded on 12/13/2009 for the course ENGG ENGL 1199 taught by Professor Bruseski during the Spring '09 term at University of the Bío-Bío.

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Key Question #3 - 1 mol = 4.97g 0.01838mol = 270.4 g/mol...

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