Key Question #13 - production of more sulphur, resulting in...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Lesson 13 Key Questions 64) K e = [NO 2 ] 2 / ( [N 2 ] [O] 2 ) = (4) 2 \ [(8)(2) 2 ] = 0.5 65) a) K e = [HF] 2 / ( [H 2 ] [F 2 ] ) b) K e = [N 2 O 5 ] 2 / ( [NO] 4 [O 2 ] 3 ) c) K e = ( [BaO] [CO 2 ] ) / [BaCO 3 ] 66) b) i) 67) The temperature affects the value of K e so the temperature must be given when specifying the equilibrium constant of a reaction. 67A) a) Removing the sulphur will cause the reaction to favour the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: production of more sulphur, resulting in the forward reaction being favoured and using up H 2 S. b) Cooling the reaction chamber or removing heat will favour the production of more heat, causing the forward reaction to occur. Experiment #5 can be found on the following pages...
View Full Document

This note was uploaded on 12/13/2009 for the course ENGG ENGL 1199 taught by Professor Bruseski during the Spring '09 term at University of the Bío-Bío.

Ask a homework question - tutors are online