Key Question #14 - therefore a precipitate is formed. 70A)...

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Lesson 14 Key Questions 68) K e = (0.01) x (0.05) \ (0.25) = 0.02 69) a) K sp = [Ca 2+ ] [SO 4 2- ] = (3.3 x 10 -3 ) x (3.3 x 10 -3 ) = 1.09 x 10 -5 b) K sp = [Mg 2+ ] [F - ] 2 = (2.7 x 10 -3 ) x (5.4 x 10 -3 ) = 1.46 x 10 -5 70) K sp = [Ca 2+ ] [OH - ] 2 = (0.066) x (0.233 2 ) = 3.58 x 10 -3 The calculated value of 3.58 x 10 -3 is larger than the K sp value of Ca(OH) 2 ,
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Unformatted text preview: therefore a precipitate is formed. 70A) Red meat releases the urate ion once the blood is saturated. By eliminating the red meat the equilibrium shifts to the left to offset the decrease in concentration. Overall this will decrease the amount of sodium urate in your system....
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This note was uploaded on 12/13/2009 for the course ENGG ENGL 1199 taught by Professor Bruseski during the Spring '09 term at University of the Bío-Bío.

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