# hw9sol - Carnegie Mellon University Department of...

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Unformatted text preview: Carnegie Mellon University Department of Electrical and Computer Engineering 18-100 Fall 2009 Introduction to Electrical and Computer Engineering Homework 9 - Due Tuesday, November 17, 2009 Problem 1: Old text 9.4, 10 points F=A*B+C*D (A,B)=(0,0);(0,5);(5,0) V (A,B)=(5,5) V (C,D)=(0,0);(0,5);(5,0) V 0 V = 5 − 0.6 10 Ω + 100 10 Ω = 4.36 (C,D)=(5,5) V = 5 − 0.6 10 Ω + 100 10 Ω = 4.36 = 5 − 0.6 10 Ω + 50 10 Ω = 4.38 For 100k resistors, a logic high is not attainable thus the function F is always 0. (A,B)=(0,0);(0,5);(5,0) V (A,B)=(5,5) V (C,D)=(0,0);(0,5);(5,0) V 0 V = 5 − 0.6 10 Ω + 100 10 Ω = 0.4 (C,D)=(5,5) V = 5 − 0.6 10 Ω + 100 10 Ω = 0.4 = 5 − 0.6 10 Ω + 50 10 Ω = 0.73 Problem 2: Old text 9.12, 10 points a.) Vin=0V, Q1 is off, LED is on: = 5 − 1.8 880 Ω + 330 Ω = 2.64 ? ? = 5 − 880 Ω = 2.67 2 = 5 − 0.6 2 Ω = 2.2 ?...
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hw9sol - Carnegie Mellon University Department of...

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