solution13

# solution13 - . 3 knots (Mach 0.38) at 10,000 ft = 382 . 6...

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650:460 Aerodynamics Homework Assignment No. 13 Prof. Doyle Knight Tel: 732 445 4464, Email: [email protected] OFce hours: Tues and Thur, 4:30 pm - 6:00 pm and by appointment ±all 2009 1

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Homework Consider a Boeing 767-300ER. Calculate the velocity in knots (nautical miles per hour) for a) maximum endurance and b) maximum range at 1) 10,000 ft and 2) 36,000 ft. Solution For a turbojet aircraft, the velocity at maximum endurance is V me = b 4 π eA ρ 2 o σ 2 ( W / S ) 2 ( f / S ) B 1 / 4 For the Boeing 767-300ER, A = 7 . 9, e = 0 . 7, W = 387 , 000 lbf, S = 3084 ft 2 , b = 156 . 1 ft and f = 127 . 5 ft 2 . Thus V me = 243
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Unformatted text preview: . 3 knots (Mach 0.38) at 10,000 ft = 382 . 6 knots (Mach 0.67) at 36,000 ft 2 Homework For a turbojet aircraft, the velocity at maximum range is V mr = p 3 C 2 C 1 P 1 / 4 where C 1 = 1 2 ρ f and C 2 = 2 ρπ e p W b P 2 Thus V mr = 320 . 3 knots at 10,000 ft (Mach 0.50) = 503 . 5 knots at 36,000 ft (Mach 0.87) Note that the use of consistent set of English units in the above formulas results in an answer in ft/sec which can then be converted to knots using 1 nautical mile = 6076 ft. 3...
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## This note was uploaded on 12/15/2009 for the course 650 460 taught by Professor Knight during the Spring '09 term at Rutgers.

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solution13 - . 3 knots (Mach 0.38) at 10,000 ft = 382 . 6...

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