ChE102-A11 - 27) 0.01 molL 1 s 1 ; k = 0.010 Lmol 1 s 1 28)...

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ChE102 Chemistry for Engineers - Assignment 11 Due: Week Beginning November 30 th , 2009 1. From Petrucci et al., 9 th Edition, 2007 Chapter 14, questions: 1, 13, 27–32, 50, 55, 58, 60, 62, 78, 83, 86, 89, 91, 94 Numerical Answers Chapter 14 1) a) 3.1 × 10 –4 mol·L –1 ·s –1 ; b) –3.1 × 10 –4 mol·L –1 ·s –1 ; c) 9.3 × 10 –4 mol·L –1 ·s –1 13) 5.70 L 2 ·mol –2 ·s –1
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Unformatted text preview: 27) 0.01 molL 1 s 1 ; k = 0.010 Lmol 1 s 1 28) 0.0100 molL 1 s 1 29) 70 s 30) 0.008 molL 1 s 1 31) a) 0.01; b) 0.0048; c) 0.0034 (all in molL 1 s 1 ) 32) a) none; b) 0.32 molL 1 ; c) 0.47 molL 1 . 55) a) 34.8 kJ/mol; b) 61 C 58) 4 60) 0 th 78) 60 s 1 86) 0.015 89) 2 nd...
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