Test 2 - Sept_2009_MATH1014A - IDCOdeRecord Test-2 in Math...

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Unformatted text preview: Sept_2009_MATH1014A - IDCOdeRecord Test-2 in Math 1014 of 6 Nov. 2009 lDCode Tfitfi Tes -2 has been graded out of 115 points. 0131 10 47 If your scored X number of points KAC2H on this test, then your letter grade 727 is in the following range: 9647 35 14 9999 56 52 3452 52 32 A+ if X 290, A if, 90 <X S 75, $233 75: B+i.f,75<X<67,Blf,67SXS6O 28AC 18 35 D+ if, 45<X<37, Dif, 37_<_XS30. 1958m 12 2 1111 41 ‘ 82 C000 72 82 ' 1 223 47 60 IDCode Test 1 Test 2 4 0415 55 7 Sh73 90 83 0914 41 12 JASON 43 43 1 105 52 49 82959 83 73 1 990 44 1 6 21337 23 9 2939 83 47 21038 29 9 MDSP 21 30 612FA| 1 7 35 011d 32 32 4868 63 45 28369 61 61 2999 59 39 th 1 S 41 19 . . DthS 38 50 M31 81 40 57 1689 62 23 24655 94 48 M07028 81 40 1 981 1 2 0414 36 40 0990 56 1 1 9876 90 54 1 1284 57 42 1246 57 1 0 2234 51 21 7 , 8250 1 07 93 BEEF 36 41 M348 32 20 M.G.90 8 5 21 12 39 47 1 509 32 6 4445 45 12 B80A 27 38 9259 38 65 2763 38 33 081 3 86 58 0720 38 58 » 47AD 45 27 2817 56 22 L458 60 40 5821 72 23 - 5678 69 47 3589 41 23 0425 49 48 0m7867 44 33 3689 23 76 1 109 60 70 R121 42 41 NK90 59 46 SOTE 79 66 3892 35 60 1 234T 1 9 30 1 252 1 05 85 1035 68 60 0218 73 34 Vn1 5 92 ~ 73 AA5617 22 JENWA 63 54 1 234K 22 1 7 - 6473 39 15 MU21 52 40 2030 50 59 73783 86 30 r D033D 54 48 Yu15 33 27 NANZ 64 57 7771 23 23 5048 40 12 2013 72 80 SY87 64 68 1234M 51 43 M000 28 28 Note: Only those who wrote noF1 15 4 t H t d 4034 22 42 v Jig-AM ’ e a°" TEME 50 32 28136 98 73 1 \0“‘3 York University I 5 g Department of Mathematics and Statistics MATH:1014 rof. H Joshi . Test — 2 er-l 6 Nov. 2009 PRINT (not scribble) - ' (Last Name) ' (First Name) (Student Number) (IDCode) Answer all guestions Erinted on Five pages. You may write on both sides of a page: The last gage is standard integrations formula sheetl DO NOT DETTACH IT. 1. (20 Points)FindJ3__2x_dx (10m -‘ Jag +2»; *4); —8 :1” x +2x “ix—8 36m +1) ~4tL)-L+l) = (Dbl) bL—rzf' “7L . g c . T :: S dk : r —_— A —+ L + @ " 3‘5 +213 ~LbL '8 km -2) bk +31 xrl {1+2} . >e+2 ‘ 2:; x 2: A buer +BL3K-‘ZD + Q bi —2)bL-+2)_ 2 Age +47L+4+) + mu— 2‘) + <1 (78 - 1+7 * , 3L : 78' (A+C) + 1 Um +5) + Um -2{5 ~40 gesismh‘mo‘ JCymvx/zfi ' r ' ' - ~:-> cz—A Joe PM . {a . :Lm-rB :9 ism—4e ,. M? We. 5 0 :Am -253 4+: :17 4A ~2U-4e) 4M) = o - - I "1—? 4a-1+8A+Lm:o 1:? /=-.2g=—g Math 1014A Test-2 g y 1 1 Page 2 of 5 I 3 I WORM! act’s 5X COS 53K : COS L53L+3Jd +CUSGJK‘3JL) 2. (10) Evaluate J—coschos3xdx r o 2 : Cos Uh.) + 003C2x) 1T _ -.__ 3 l 1T I i ,3 . .3: 50 ngsSX c0531 Ax. = (c,an +C0529L) 5" ® __ _ _3. - .32. - 7 31 spn5x+z$m1x10 GD : o . @ 3.|(20)Eva.luate'[ ' dx M 1:361“? _ x2 x2” de—Smclede I: Sw—i—wax zj ”__;_é_w_~_ ....... __., gmze 59*" 96h”? fitm’eJ Ware-+01 - : S Mjiagéglewm:x 0‘9 : 5 2 male \OHCMZBJ Q1Ll+—tmée) _ “Cane 39209- .. _|_____L_' 90319. “i rose ‘ I 6)) m Q16 :j 5 dBS-Q 5136 de ’ 55 sme 'S'ma d9 cote CSCG d9 : ——J?; cScei-EC C=W z. ,_ “‘2 2 LL 7L\§\ mn6:3§ CZJC‘S‘B :TjCfl-gioJX'F-Q’ J9 ‘+°1 - x“ __ C # 39+ J 5 LA CSC 9:; Elia—e .— 9L ’ )L l .— __..L Jk}+q I-*€_CSCG+C—— .3 #DL _+C @ = — E + c 2,. Math 1014A Test-2 2 P e 2 of 5 2. (30) Use integration by parts to prove the formula n—I ‘ [2 cos xsmx n—l _ . . ” Jcos" x dx = —+ —jcos" 2 x dx and use 1t to evaluate Icos4 x dx n n o ‘ VI ‘ 7‘ "-l \ 4 1 zj C05 de— [005 X “Sde ‘J 60; x c4 Su‘nx "" n~l . ma 2 gogx sinx ~ anx damn-Ix : Casx SMX~ sz‘Ax- (n~l).cosag n—l I ('* anx)cl>( __ \ ‘ l “‘2 . — Oofi X SIAX + CV1“) ySmX 00S dX @ :— C/os‘MX “IL, (“—1) f(l~—(/052}()OOSM~2XCIX :. cosw‘x Sit/xx + (H-UJCOSk‘XdX ~ LVVOT h h COS X64” @ when flzl—t 3’ 1\ 2L 11 1 (2954de I: W 2 3 l a 4r o +-~ cosde a ., 4 v @ 1, :‘fl WX IE % cl) >_ :F l 0 l X s % __ Nx‘ 3‘ ‘r 3‘1 Math 1014A Test-2 1 P 64 of 5 5. (20) Determine whether I 2 4-; +2 dx is convergent or divergent. Evaluate, if it is convergent. 1 m: I ....._ A B _) AbL-FZ) +5Lx+0= 3L1+33L+l — (Dc-H) (1+2) Dczyz ____I_> B=~f I 12-! ""9 92‘ we W? __ '00 I 00 f _ I - I * S 1 ml+3x+l A)“ Z 5 I, (1+! 1+2) (ha \mow5 \‘ __ . t 1 __ a I Vb ' (if? M 7 5i (NH w”) Ax fie ‘3 ', -. 3:94 W3 ’m K)me WI) W M 4i \L - i igi‘fivmx : [ \Qn{:l3L-+l|)-'VQMUDL+1|) 7‘ 7| : 1W [anwc : “mph 13:1) 4,, 23.)] t‘ew \Ukrl‘l‘ __ I face lt+l \ _ 4mg) = JAB) um) a: o 4055 ‘ I A" /' W m t-—>00 It—HI ~>_09_ (Kr MW-‘L fiwfl It+l\ 00 i “9" “53° Han) "" “9” “CW I Math 1014A @- :Q #115) 6. (15) Compute the area bounded by y = Pa eSOfS y=0,’from x=0 to x=3. dx Test-2 l 2 V9—x2, 3 (Q o JQ'DJ _ 3k =5 62 W30) 01x ® ...
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Test 2 - Sept_2009_MATH1014A - IDCOdeRecord Test-2 in Math...

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