# HW3 - k Prob|em 216 2.16 A single axial load of magnitude P...

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Unformatted text preview: k, Prob|em 216 2.16 A single axial load of magnitude P = 58 kN is applied at end C of the brass rod ABC. Knowing that E = 105 GPa, determine the diameter d of portion BC for which the deﬂection of point C will be 3 mm. \$C:EP2L.; = £{LM3 4.523% A-3E E AAB AB; _ (tafxlo‘)(3x/0f3) [-2 3 _' ‘ 53a<103 “‘ ———'g(0_030)z = 3.7334xzo m 0.3 _ = —-—-———— = almaleo ‘m 3.7331x103 3,7334 wo3 _ Ir]- ‘7- I: L I.‘ - Au ~ rt- cpac .. dag: ’ 11TH“ : ./ (“(zwﬁfaﬂo ) : [6.52YIO 3In» = l6.52 IMM 2.19 Two solid cylindrical rods are joined at B and loaded as shown. Rod AB is made of steel (E = 29 X 106 psi), and rod BC of brass (E = 15 X 106 psi). Determine y (a) the total deformation of the composite rod ABC, (b) the deﬂection of point B. sin. Podium A8: Pm: 40x10“ 1%, L‘m atom.) a: AAB -: = £L(2)t =' 3.!‘Hé ['52) EM.- 25/51/0‘ losf ~ _ PAQLAB _ (Llouoalwo) _ -3, 30kips 5”" EABA“ ' (quloaxawlé‘) - \7.56W xlO M. 2m. Por‘l’fow BC I '~‘ - 201K103 fly) L5c = 30 in.) A? 3 in.) Arse: 130,1: §<3l1 = 7.06361};2 , Egg: l5>‘/Oé Psi P=40kips : : (—20KIO3)(303 : _ Q —s .n. S‘“ Egg/43¢ (15xio‘)(7_ocszo 5' 538’") ' (on S = 3.6 + S“ : H.597 xlO-‘— 5.6588 x10" 5? Hﬂowo'3 in!“ 53 = ’33: \$3: 564540 134.1" ‘ Problem 2 2.22 The steel frame (E = 29 X 106 psi) shown has a diagonal brace BD with an area of 3.2 m2. Determine the largest allowable load P if the change in length of member BB is not to exceed % in. P _ _L . . \$39 - u, m. : 0.0e23‘ m. LSD 71/51-l 67' -“ 7.8!02 "Ft —' 93.723 in. _ F Le EA 3 8°- ?”Ki‘ Fen -‘ 35:53“ F , (2avioéX3.23§o.oez5) : 3 3:: 93.723 GLSSHHO ﬂA. USe Join'l B as CK. ‘Frte iZF—xco: "P'l 5 Fat. 3 CD B P 7.2109. " ' 5 f P: (5)(él.824x103 =, __ . FAG ED 7- ‘ ers Problem 225 2.25 MembersABC and DEF are joined with steel links (E =200 GPa). Each of the links is made of a pair of 25X35-mm plates. Determine the change in length of (a) member BE, (b) member CF. Use. member ABC 4.5 a-Fwee, heel? 32MB=0 (Oﬁcbmzétoﬁ — (0.32MB; = 0 Fe‘: :W)- Zéxloz N .. Is kN 0"30 DZMc = 0 (Am: )(l8 Ho’) + (0.180) Egg :0 3 Area —l:w~ pink Ma)? PM, =-—————(°'qgf’ll8(é3xlo) : _ 44 x103 N mt +00 Male: .3 A = (a 3(0.025')(o.035) = 1.7020 m‘ _ EELS? (— '44 xI03)(O.2‘/o) -6 (6”) S“; E A ‘ (ZDOYLOllUJSHO’g) “sogx'o M ‘ -0‘0302 m“ .3 3 Q 00} SC: = Fe: LcF — W1,— /7_ say/0. m = 0.01783 mm Q EA ‘ (Zooxtoqusuo-J): ...
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HW3 - k Prob|em 216 2.16 A single axial load of magnitude P...

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