HW2 - Prob|em 1 '32 1.3.2 Two wooden members of uniform...

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Unformatted text preview: Prob|em 1 '32 1.3.2 Two wooden members of uniform cross section are joined by the simple scarf splice shown. Knowmg that the maximum allowable tensile stress in the glued splice is 75 psi determine (a) the largest load P that can be safel , _ ‘ su rt d correspondlng stress in the splice. ‘y ppo e 3 (b) the = (5.0mm? 15ml A0 9 90° ~GO° : 30” 6 PC0526 1' O (a) PT EAO :»(75)(153 1 , (:03 6 6057‘ 30° r 1500 Jr, P T LSOO ktps <1 : : (IS—DO)S;»\[DOO Mo (2)053 filigrugfsi ‘ Prob|em 1 _34 1.34 A steel pipe of 300-mm outer diameter is fabricated from 6-mm-thick plate by welding along a helix that forms an angle of 25° with a plane perpendicular to the axis of the pipe. Knowing that the maximum allowable normal and shearing stresses in the directions respectively normal and tangential to the weld area: 50 MPa and 1:: 30 MPa, determine the magnitude P of the largest axial force that can be applied to the pipe. dc: 0-300"! {\°=%0'°: r-=Y‘o-t = 0.!50—o.006 = 0.149,“ A = 1t(r°"-r‘,;‘3= 77'(0.I$o"-o.m#‘) : 5,54 x/O'S m" r2 6: WP C0529 -3 o > é 5.9-! ’40 35°le ; 337x/o3 * 6°57" 25° Basal on l=’Zl = 30 MPa. 2: = % sin 29 P: 3A2}... : {‘ZXSZSflxlO'?’ onloél = 434x703 SM 25 . sin 50‘: Smaflew VAL/C is ‘H\e value (If? of: P: “553 Prob|em 1 _ 3 5 1.35_ A 240—kip load P is applied to the granite block shown: Determine the resulting maxunum value of (a) the normal stress, (b) the sheanng stress. Spemfy the orientation of the plane on which each of these maximum values occurs. A, = (en‘s) = 36 M 6 : ~E— C0316 = 63515 = ‘6.67 c096 6 (OLD Moot: +ensffe s'i‘ress ; 0 ad- 9 = 90: Maw. mewphebsive. s-lvess = 6.67 Low d ail e = a“ f.“ = i 2" *fl = ‘ ~+ e = 45° Problem 1 1.37 Link AB is to be made of a steel for which the ultimate normal stress is 450 MPa. Determine the cross—sectional area for AB for which the factor of safety will be 3.50. Assume that the link will be adequately reinforced around the pins at A and 8 kN/m B" Pr mum = 7.4 m F“. P r 0-9m \\_ E MD = D V «(0.‘8XFM3 sat 35") + (0.2mm Q Dy {0-33003 = O F“, = new w = 2!.élfix103 N‘ — _ git. _ (ES-7 Ra _ (3.503g21.e1w|03) 6A3 ‘ AM3 - —— _ 5.,» I150 >1 [06 1 : IGSJ xlo“ w. AM: MBA mm‘ A Problem 1 .40 1.40 A steel loop ABCD of length 1.2 m and of 10-mm diameter is placed as shown around a 24-mm-diameter aluminum rod AC. Cables BE and DF, each of 12-mm diameter, are used to apply the load Q. Knowing that the ultimate strength of the steel used for the loop and the cables is480 MP3, determine the largest load Q that can be applied if an overall factor of safety of 3 is desired. Usin ‘oiai‘ B 05d¥¢eL boat Q ‘l J , ‘ a and coflfitde’lfi} symmex‘i‘lea 5. J 2'%‘Eg "' Q = 0 E5 FAB Q= g5“ Usfaa joia‘l‘ A 4.5 axltv‘ee <FM'L and considering Symme‘l’W—I 4......— p}: 2-:‘$Re~Re =0 F“ goele — File. so .1 Q: 3-1:; Based? m. sheen-ll or Calla/e BE Q» ~= 63A = 62 143a!" = (wsoxlo‘) HM"le = 541W“? N Based on slope-43% a": sled 1700': 520 t ‘33er : 'E‘GZJA = £56313” = %<480xloé)£(0.010)z : 45.24 v/os N Basal on 5+v~enjH1 o'P bod AC G» — em, = em, = $631356” : %\(:té,o>vto")‘71E(0.02%)1 = 88.22 x103 N Adam? affine/+3 [DJ 0.) is 7%: shafies'l‘ Q0: 45'. 29x103 N 3 Q Alkyd/V2. ’90“! 6).“ Egg : = (5.08XIO N = L502 M) d Problem 1.44 110k}; --—~ "me 1.44 Three 18-mm-diameter steel bolts are to be used to attach the steel plate shown to a wooden beam. Knowing that the plate will support a 1 lO-kN load and that the ultimate shearing stress for the steel used is 360 MPa, determine the factor of safety for this design. F“ 6”“ 500* A = '3 0'2 -‘ We? T 25147 m} = 25a.47></o" ml Pu = A Tu r (25%-q7x/o“l(3éox [06) = 9|.éofi x103 N For Hue 'Hwee Buffs PU 7 (3l(‘1/.60‘?&{O3) = 27%-83 x/03 N Fac+or a“? 5663\847 Pg : 3L, zmwog W : 2-50 «A P “owes ...
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HW2 - Prob|em 1 '32 1.3.2 Two wooden members of uniform...

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