I-16 - i=0 => f(x-0)= f(x)=1 i=1 => f(x-1)= f(x-1)=1...

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17 Math of convolution • x is the pixel of interest, i.e., the position in the signal/image AND the center of the filter 1 1 2 2 1 1 2 2 1 1 1 2 1 f(x) i=-1 => f(x-(-1))= f(x+1)=2
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Unformatted text preview: i=0 => f(x-0)= f(x)=1 i=1 => f(x-1)= f(x-1)=1 ∑-=-= = n n i i x f i h x f h x g ) ( ) ( ) ( * ) ( { } ∈-∈ ⇒ = 1 , , 1 1 i n {...
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This note was uploaded on 12/20/2009 for the course ECE 506 taught by Professor Staff during the Fall '09 term at Clarkson University .

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