D-12 - Scl= n ± j n(1 ω ω ^2)^.5=.8 ± j.7 809.28 It is clear that a gain controller alone will not allow these poles to be reached with the

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Unformatted text preview: Scl=- * n ± j* n*(1- ζ ω ω ^2)^.5= -.8 ± j*.7 ζ 809..............................28 It is clear that a gain controller alone will not allow these poles to be reached with the given plant. We can then design a controller with zeros at 100 and 1.32 as to cancel the poles of the plant. Looking forward we will not cancel the pole at zero as its inclusion will allow for a steady state error to a ramp. The controller will also include a pole at -1.6 so that the breakaway point will lay on -.8 and can then be controlled secondly by a gain to reach the desired closed loop poles. 16 Gp(s) = ------------------ s (s+100) (s+1.32) K*(s+100) (s+1.32) Gc(s) = ---------------------- s (s+1.6) 16*K*K...
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This note was uploaded on 12/20/2009 for the course ECE 451 taught by Professor Staff during the Fall '09 term at Clarkson University .

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D-12 - Scl= n ± j n(1 ω ω ^2)^.5=.8 ± j.7 809.28 It is clear that a gain controller alone will not allow these poles to be reached with the

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