ps6-solutions

ps6-solutions - I ntroduction to Computer Science and Java...

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Introduction to Computer Science and Java Programming, Fall 2009 Problem Set 6 Chapter 7 4. 2.5+2.5 = 5pts (for part a, answers may vary depending on the assumptions they have made. Make sure that their assumptions are reasonable) a. Recall from chapter 5 that a megabyte can store about 2.5 books. Therefore, to store one million books, one would need 1,000,000 / 2.5 = 400,000 megabytes = 400,000,000,000 bytes. b. The amount to be transferred is 400,000,000,000 * 8 = 3.2 * 10^12 bits = 3,200,000 Mbits. At the rate of 10 Mbps, the transfer time would be 3,200,000 Mbits / 10 Mbits/second = 320,000 seconds At the rate of 1 Gbps = 1000 Mbps, the transfer time would be 3,200,000 Mbits / 1000 Mbits/second = 3,200 seconds 10. 5pts The store-and-forward protocol would handle a packet repeatedly getting sent from node A to B but not correctly arriving by finding another route on the network from node A to B and retransmitting every lost packet on that new route. Modifications we could make to this protocol to handle this particular situation are to number each of
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ps6-solutions - I ntroduction to Computer Science and Java...

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