# PS6s - SOLUTIONS TO ISMT111 PROBLEM SET#6(1 Answer 98.0 n =...

This preview shows pages 1–2. Sign up to view the full content.

SOLUTIONS TO ISMT111 PROBLEM SET #6 (1) Answer: 98.0% n = 9 , (small); x = 83 . 7 , s = 12 . 9 , σ = unknown; X approx . normal . B = 96 . 153 - 83 . 7 = 12 . 453 = t 12 . 9 9 ; t = 2 . 896 ( df = 8); Answer = 2 × (0 . 5 - 0 . 010) = 0 . 98 . (2) Answer: (8 . 1984 , 12 . 9416) n = 100 , ( > 30); x = 10 . 57; s = 12 . 10; σ = unknown; Distribution ? Use z = 1 . 96 10 . 57 ± (1 . 96) 12 . 10 100 = 10 . 57 ± 2 . 3716 (3) Answer: - 24 . 3/ c to 64 . 3/ c . From the given data: n = 9 , (small); x = 0 . 2 , s = 0 . 714 , σ = unknown; X assumed normal. Use t with df=8 x ± t s n ; 0 . 2 ± (1 . 86) 0 . 714 9 . (4) Answer: 71 n = ± z σ B ² 2 = ± (2 . 33)(18) 5 ² 2 = 70 . 358 (rounded up to 71) . Note: If you read z = 2 . 32 from the z-table for 0.4898, you don’t meet the required minimum of 98% conﬁdence level. (5) Answer: (2 , 120 . 72 , 2 , 679 . 28) x = 2400 , n = 17 , ( < 30) Given σ = 700 , and normality . Use z = 1 . 645 2400 ± (1 . 645) 700 17 = 2400 ± 279 . 28 (6) Answer: 0.3 ± 0.0635 95% Conﬁdence Interval for p = z = 1 . 96; b p = 60 / 200 = 0 . 3 , b p ± z p b p (1 - b p ) /n = 0 . 3 ± (1 . 96) p (0 . 3)(0 . 7) / 200 (7) Answer: .950 Given the interval (14.775, 17.225), n = 64 , ( > 30) , x = 16 ,s = 5 , what is z so that 17

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

PS6s - SOLUTIONS TO ISMT111 PROBLEM SET#6(1 Answer 98.0 n =...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online