Unformatted text preview: , < 1 . 309 of Model B, and < 1 . 341(= √ 1 . 79743) of Model A ); (3) Model C has all its coeﬃcient estimates (the beta hats) signiﬁcant at, say, α = 5%, (i.e., all pvalues smaller than 0.05). (6) (a) True. S 2 Y = SST/ ( n1) = 166 . 364 / 76 = 2 . 189 (b) False. The coeﬃcient of SENIOR in Model B has a pvalue of 6.5%, greater than 5%. (c) False. Note: The reciprocal of SENIOR is used in Model C. (d) False. The correct value is √ MSE = √ 1 . 79743 = 1 . 341 . (e) True. = b β 5 ± t . 025 ,df =69 S b β 5 =. 06391 ± (1 . 994945)(0 . 04800) ≈ (. 1597 , . 0319) (Note: t . 025 ,df =69 = 1 . 994945 is obtained from Excel. Using z = 1 . 96 would produce a less accurate answer of (. 15799 , . 03017). I should have set this question (e) with this answer instead.) * * * 1 ATChan 2008...
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 Fall '09
 AnthonyChan
 Null hypothesis, Statistical hypothesis testing, 5%, 6.5%, 60.6%

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