realev - Since we have one positive and one negative...

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MATH 342-010 Di f erential Equations with Linear Algebra II Sep Sep 16 2009 Phase Plane: Real Eigenvalues For the system = x the solution is x = c 1 e 5t + c 2 e− 5t
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Unformatted text preview: Since we have one positive and one negative eigenvalue, we have a saddle point, as shown below. Note the straight lines corresponding to the eigenvectors....
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This note was uploaded on 12/23/2009 for the course MATH 342 taught by Professor Edwards,d during the Fall '08 term at University of Delaware.

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