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Unformatted text preview: Supplementary Notes ltsziAf'fW A general solution for the maximization problem of two inputs—one output CeD production. Suppose the production function is given by q: LQKﬁ where a > 0,13 > O and a+ﬁ <1
Step 1: Set up the maximization problem Ti' =pL‘1Kﬁ — wL —— T'K Step 2: Find FOC g:— * paL““1K’9—w:0
8
i = pﬁLﬂKﬁd—wto Step 3: Find the relation between L and K posLQ‘lKﬁ w pﬁLaKﬁ*1 _ Then, It follows that Step 4: Plug it into one of equations in the FOC J6
paLaﬁ‘ﬁﬁl = w
T G Then, Denote L“, K * and q* as the proﬁt maximizing amount of labor, capital and corn, respectively. Let 6:1u(a+ﬁ)>0. Hence, I; 2 p1/9a(1‘5l/6ﬁ5/waill/0T—3/9 Plug E“ into (1) to get K“. K* = pl/Baa/‘Bﬁﬂ—a)/6wia/9r(a—1)/6 and (1* = (ma WW Notice that these are functions of p, w and 7'. You can check how L*, K* and q* change with respect to p, w and r by taking the partial derivative of each function with respect to each parameter. 815* 1 2 _ (um—1 (1—m/a ﬁ/ﬁ (rs—1W 43/9
6p 6p a B m r >0
3“ _ (ﬁg—1) (1/0) (hm/a 6/6 «mum—1 we
5w _ 6 p a 6 w T <0
an
ar : _gPU/m—1a(143)Ngﬂ/wa—IVSTEﬁ/m—1 < 0 Similarly, the partial derivatives of K* with respect to p, w and 'r can be derived. Then, for (1*, you can use the chain rule to see the Sign. a * a; 315* a , m
6‘; = am) 1 6p (K*)5+B(L*) (W)ﬂ 166p
6 * 815* K
79: ~ a(L*)“‘15w(K*)’3+ﬁ(L*)“(K*)ﬁ'163w
851* _ >5: owl 615* at ,6 * C! * {3’1 a? a(L) 6? (K) +£(L) (K) 81" ...
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 '06
 MASSON
 Microeconomics, Derivative, 1K, 5w, 1W, 5L, maximization problem

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