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HW1_Solutions_09

# HW1_Solutions_09 - Phys 1112 Homework 1 Solutions Spring...

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Unformatted text preview: Phys 1112 Homework 1 Solutions Spring 2009 1. Y & F Problem 1.12 The length of the year in seconds is 365 . 24 days × 24 hours 1 day × 3600 seconds 1 hour = 3 . 1557 × 10 7 s Keep 5 significant figures. Take π from your calculator, which carries at least 10 significant figures, so this uncertainty is negligible, The ratio of the two time intervals is π × 10 7 s 3 . 1557 × 10 7 s = 1 . 0045 Again 5 significant figures. The two numbers differ by 0.45 %. 2. (a) 24 mi / gal = 24 mi × 1 . 609 km / mi 1 gal × 3 . 788 L / gal = 38 . 6 km 3 . 79 L = 100 km 3 . 79 L × 100 38 . 6 = 100 km 9 . 8 L It takes 9.8 L to drive this car 100 km. (b) 5 . 5 L 100 km = 5 . 5 L × 1 gal / 3 . 788 L 100 km × 1 mi / 1 . 609 km = 1 . 45 gal 62 . 2 mi = 1 gal 62 . 2 1 . 45 mi = 1 gal 42 . 9 mi Pretty good gas mileage: 43 miles/gallon! (In the 1960s, a 2-cylinder FIAT 500 needed about 6 L per 100 km, a French 2CV was similar.)....
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HW1_Solutions_09 - Phys 1112 Homework 1 Solutions Spring...

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