{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# Lecture29 - Lecture 28 Project 7 Gaussian Elimination and...

This preview shows pages 1–12. Sign up to view the full content.

Engineering 101 Engineering 101 Lecture 28 Lecture 28 Project 7, Gaussian Elimination and Project 7, Gaussian Elimination and MATLAB MATLAB Prof. Michael Falk University of Michigan, College of Engineering

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Announcements Announcements Exam 3 Monday, Nov 20, 7-9pm Sample Exams now posted, Review Friday Exam Rooms by Last Name: A-B Dow 1018 C-G Chrysler 133 H-K Dow 1017 L-O Dow 1014 P-Z Chrysler 220 (Cheseborough) Early Administration, Fri, Nov 18, 3-5pm in CSE 1670 Contact me today if you need to take the exam early So far: Jack Hall, Alex Lee, Marcus Lewis, Nat Christman, Noah Goodman, Nick Beier, Kaushik Seshan
Project 7 Project 7 This is an intro to MATLAB with 2 parts Part 1: Write an M-File to solve for the flows in a chemical reactor making methanol Start with the diagram and use it to come up with 15 equations for the 15 unknowns. Compose these into a 15x15 matrix and solve using a MATLAB M-file.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Project 7 Project 7 Part 2: Write two MATLAB M-files containing functions Function 1 - playit(‘filename’, start, duration) Plays a sample clip from start of length duration. Function 2 - mixit(‘filenameA’, ‘filenameB’, ‘filenameC’, start, duration) Convolve a short clip from B from start of length duration with the sound in A. Play the result and write it to C.
Tomography Tomography How can we compute the mass through which each beam passes? First row: 8 ρ 0 = m 0 Second row: 2 ρ 0 + 6 ρ 1 = m 1 Third row: 2 ρ 0 + 2 ρ 1 + 4 ρ 2 = m 2 Fourth row: 2 ρ 0 + 2 ρ 1 + 2 ρ 2 + 2 ρ 3 = m 3 ρ 0 = 0.1 ρ 1 = 0.2 ρ 2 = 0.5 ρ 3 = 1.0 m 0 m 1 m 2 m 3 m 3 m 2 m 1 m 0

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Tomography Tomography How can we compute the mass through which each beam passes? 8 ρ 0 = m 0 2 ρ 0 + 6 ρ 1 = m 1 2 ρ 0 + 2 ρ 1 + 4 ρ 2 = m 2 2 ρ 0 + 2 ρ 1 + 2 ρ 2 + 2 ρ 3 = m 3 ρ 0 = 0.1 ρ 1 = 0.2 ρ 2 = 0.5 ρ 3 = 1.0 m 0 m 1 m 2 m 3 m 3 m 2 m 1 m 0
Tomography Tomography How can we compute the mass through which each beam passes? 8 ρ 0 = m 0 2 ρ 0 + 6 ρ 1 = m 1 2 ρ 0 + 2 ρ 1 + 4 ρ 2 = m 2 2 ρ 0 + 2 ρ 1 + 2 ρ 2 + 2 ρ 3 = m 3 8 0 0 0 ρ 0 m 0 2 6 0 0 ρ 1 m 1 2 2 4 0 ρ 2 m 2 2 2 2 2 ρ 3 m 3 ρ 0 = 0.1 ρ 1 = 0.2 ρ 2 = 0.5 ρ 3 = 1.0 m 0 m 1 m 2 m 3 m 3 m 2 m 1 m 0 =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Tomography Tomography Of course the problem of finding the mass of a slice is not the problem we are usually interested in solving. We can measure the masses of the slices by tomography. We want to know the density of the rings given the masses of the slices. This is straightforward if the matrix is triangular.
The Inverse Problem The Inverse Problem 8 0 0 0 ρ 0 m 0 2 6 0 0 ρ 1 m 1 2 2 4 0 ρ 2 m 2 2 2 2 2 ρ 3 m 3 Getting the first density is easy: A 00 ρ 0 = m 0 ρ 0 = m 0 / A 00 =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
The Inverse Problem The Inverse Problem 8 0 0 0 ρ 0 m 0 2 6 0 0 ρ 1 m 1 2 2 4 0 ρ 2 m 2 2 2 2 2 ρ 3 m 3 Getting the second density is a bit harder: A 10 ρ 0 + A 11 ρ 1 = m 1 ρ 1 = (m 1 - A 10 ρ 0 ) / A 11 =
The Inverse Problem The Inverse Problem 8 0 0 0 ρ 0 m 0 2 6 0 0 ρ 1 m 1 2 2 4 0 ρ 2 m 2 2 2 2 2 ρ 3 m 3 Getting the third density is similar: A 20 ρ 0 + A 21 ρ 1 + A 22 ρ 2 = m 2 ρ 2 = (m 2 – A 20 ρ 0 – A 21 ρ 1 ) / A 22 =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern