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EEE_Exam Question 3

# EEE_Exam Question 3 - Givm HUQkZL(1w LCRSRLHmLm RL R5RL R5...

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Unformatted text preview: Givm HUQkZL (1w) LCRSRLHmLm +RL)+R5RL R5 =5 k9 C=5nF RL=50kQ L=2 mH ja)[2mx50k) [jmfpmx 511 x skxsok}+ jazm(sk+50k)+[skx50k) le'GaJ —w2{25x1073)+}110w+[250x106) H050}: H00): (3) Agra—>0,H[ja))—>0 Andas (0—)00, H(jm}—>0 So, this is a Second order Band pass ﬁlter. (b) 100 j .3 0) Hum) : 25x10 7 +j 1115fI w 250><HTS 2.5x 1.0a 2.5xlO’E . 1400004.: H :— (W) in): +144000w+101l . a) _ _ _ git—”m Comparing thls With standard form: HUM) : —0Jl +j%m+r:0§ Resonant frequency a)” = #10” (q, =316.23 hadfs {0) ﬂ : 44000 Q 6’“ =22000 2Q 1 _ 22000 29 60., 1 22000 E—3lé.23x103 1 —=0.07 29 Damping ratio 4 =\$ g: 0.7 {d} E = 44000 Q .'.BW = 44 kradfs {6) Q Halfpowcr frequencies; 5912 :17 + 212 =:22000+‘ 220002 +[31623x103r q; 21220004415994 all =—22000+316994 5-)] =295 kradfs 612 =22000+316994 a)z = 339 kradfs ...
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