5 - February March 55 1115 Tu WeTh Fr 55 55 115T5 WeTh Fr...

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Unformatted text preview: February March 55 1115 Tu WeTh Fr 55 55 115T5 WeTh Fr 55 12545521254551 551511121514 551511121514 1515111515 25 21 1515111515 25 21 22 25 24 25 25 22 25 22 25 24 25 25 22 25 23 33 31 4:0 13:0 13:0 23:. January 55 1115 Tu We Th Fr 55 123 4 3 3 I" 3 313 1112131413131? 1313 2D 21 22 23 24 23 23 2? 23 23 33 31 4:0 13:0 1?:0 23:. 2:0 3:0 13:0 24:. April 35 MeTu We Th Fr 35 1 2 3 4 3 3 1' 3 31311 12131413131213 13 23 21 22 23 24 23 23 2? 23 23 33 May June 35 1115 Tu WeTh Fr 35 35 MeTu WeTh Fr 35 1 2 1 2 3 4 3 3 343323323313111213 13111213141313 1413131? 131323 1}“ 1313 23 2122 23 2122 23 24 23 23 2? 24 23 23 2? 23 23 33 23 23 33 31 2:0 3:0 1?:0 24:. 1:0 3:0 1?:0 24:. 33:0 1":0 13:0 22:. 23:0 July 55 MeTu We Th Fr 55 1 2 5 4 5 5 1 5 51511 12151415151215 15 25 21 22 25 24 25 25 21' 25 25 55 51 August September 55 1115 T5 We Th Fr 35 55 MeTu 11.111eTh Fr 55 1 1 2 5 4 5 25455255155151112 5151112151415 15141515121515 15121515 25 2122 25 2122 25 24 25 25 25 24 25 25 21' 25 25 2? 25 25 55 3D 31 T:0 13:0 21:. 23:0 3:0 13:0 23:. 2?!) October 55 1115T5 We Th Fr 55 1 2 5 4 5 5 1' 5 515 11121514151511“ 1313 23 2122 23 24 25 23 2? 23 23 3D 31 4:011:013:.23:0 4:0 11:0 13:. 23:!) November December 55 1115 T5 WeTh Fr 55 55 115T5 WeTh Fr 55 1 2 5 4 5 5 1' 1 2 5 4 5 551511121514 5155151112 1515111515 25 21 15141515111515 22 23 24 23 23 2? 23 2D 21 22 23 24 23 23 23 3D 2? 23 23 3E] 31 2:0 3:0 13:. 24:13l 2:0 3:0 13:. 24:0 31 :0 Find the final discount date and the net payment date for an invoice dated June 12 with terms of} -' 15. net 20. The final discount date is 45 -' 2]" . [Tvpe whole numbers.) The net payment date is I" -' 2 . [Tvpe whole numbers.) Find the final discount date and the net pavment date for an invoice dated Julv 5 AS OF Julv 13 with terms ofS -' 15. net 20. The final discount date is I" -' 28 . (Tvpe whole numbers.) The net payment date is 8 -' 2 . (Type whole numbers.) Edusoft an. offers customers a trade discount of 12 -' ".I‘ -' 8 on all in- stock products with terms of net 30. Find the net price for products with a total list price of $815.88 if the invoice was paid within 20 davs of the invoice date. The purchaser will receive the trade discount. The complements of the individual discounts are 0.88. 0.93. 0.92. The net cost equivalent for the series is 0.252928. The list price is $815.88 and the net cost equivalent for the series is 0.252928. So the net price is $014.30. An invoice is dated June 21‘ with terms 5 -' 18 EOE-I. Find the final discount date and the net pavment date. The net pavment date is 28 davs after the filal discount date. L'sing EDIE-1 billing the date used to calculate the final discount date and the net pavment date is June 38. When the invoice date is late in the month suppliers give customers an extra month to meet the terms of the invoice. The first invoice date in the month on which a customer will get the extra month is the 2oth. Thus the final discount date is August 18. The net pavment date is 28 davs past August 18. This is September T". So if an invoice is dated June 2'." with terms 5 -' 18 EOE-1. the final discount date is August 18 and the net payment date_ 28 davs after the final discount date_ is September '1'. An invoice is dated Julv 24 with terms 5 -' 1E1 - 28 x. Find the final discount date and the net pavment date. The net pavment date is 28 davs after the final discount date. The terms '5 -' 18- 28 x' means that the customer has 18 days ph1s an additional 28 davs or 38 davs altogether to receive the cash discount. The final discount date is 38 davs past Julv 24. lulv 24 - 3E1 davs is 23 davs past the end oflulv since 11113: has 31 davs. Thus the final discount date is August 23. The net pavment date is 2G davs past August 23. August 23 - 2E1=August 31- 12 This is 12 davs past the end of August or September 12. So if an invoice is dated Julv 24 with terms 5 -' 18 -2D :9; the final discount date is August 23 and the net pavment date. 28 davs after the final discount date. is September 12. The Coffee Comer receives an invoice amounting to $344.60 with terms of S -' 11. net 42. The invoice is dated 3 -' 17'| AS OF 9 -' 9. If a partial payment of $269.60 is made on 9 -' 17'. find the credit for the partial payment and the balance due on the invoice. The partial payment was made in time to receive the discount. The formula to calculate the credit C. for a partial payment of $P receiving a discount of D33 is c=P-(1—D-1oo)_ Applying the formula C =P -' (1 -D -' 166) with P = $269.66 and a discount of 5%. the credit is $233.29. Since the customer receives a credit of $233.29 on an invoice amount of $344.66. the remaining balance is $69.81. ...
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This note was uploaded on 12/30/2009 for the course MATH 1220 taught by Professor Roarty during the Spring '09 term at Metropolitan Community College- Omaha.

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5 - February March 55 1115 Tu WeTh Fr 55 55 115T5 WeTh Fr...

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