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# hwk2_sol - ISOM 111 L6-L7 Fall 2009 1 Homework 2 Due Monday...

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ISOM 111 L6-L7, Fall 2009 1 Homework 2 Due: Monday, Oct 5, 4:00pm I . Problems 3.24 (p.146) of the textbook. Solution : (a) P (manager MBA) = P (manager) P (MBA | manager) = 0 . 15 × 0 . 60 = 0 . 09 = 9% (b) P (manager | MBA) = P ( manager MBA ) P ( MBA ) = 0 . 09 / 0 . 25 = 0 . 36 = 36% . (c) No. P (manager | MBA) 6 = P (manager). Alternatively, one can firstly figure out a contingency table, and start from there: MBA No MBA Manager 0 . 15 × 0 . 60 = 9% 15% Non-Manager Total 25% 1 MBA No MBA Manager 9% 6% 15% Non-Manager 85% Total 25% 75% 1 MBA No MBA Manager 9% 6% 15% Non-Manager 16% 69% 85% Total 25% 75% 1 P (manager MBA) = 9%, P (manager | MBA) = 0 . 09 / 0 . 25 = 0 . 36 = 36% . II . Problem 3.30 (p.146) of the textbook. Solution : (a) 0 . 9973 50 0 . 874 (b) x 50 = 0 . 9973 x = 0 . 9973 1 / 50 0 . 999946

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ISOM 111 L6-L7, Fall 2009 2 III . Problem 3.56 (p.151) of the textbook. Solution : (a) P (Alaska delayed) = 501 / 3775 0 . 133 P (America West delayed) = 787 / 7225 0 . 109 America West has a smaller percent of flights delayed overall. (b) P (Alaska | LA) = 62 / 559 = 0 . 111 P (America West | LA) = 117 / 811 0 . 144 P (Alaska | Phoenix) = 12 / 233 = 0 . 052 P (America West | Phoenix) = 415 / 5255 0 . 079 P (Alaska | San Diego) = 20 / 232 0 . 086 P (America West | San Diego) = 65 / 448 0 . 145 P (Alaska | San Francisco) = 102 / 605 0 . 169 P (America West | San Francisco) = 129 / 449 0 . 287 P (Alaska | Seattle) = 305 / 2146 0 . 142 P (America West | Seattle) = 61 / 262 0 . 233 Alaska Airlines had a smaller percent of flights delayed at each airport.
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hwk2_sol - ISOM 111 L6-L7 Fall 2009 1 Homework 2 Due Monday...

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