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hwk6_sol

# hwk6_sol - ISOM 111 L6-L7 Fall 2009 1 Homework 6 Solutions...

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ISOM 111 L6-L7, Fall 2009 1 Homework 6 Solutions I . Problem 10.22 (p.403) of the textbook. Solution : (a) Based on the data provided, n = 12 , X x i = 548 , X y i = 5782 , X x 2 i = 34978 , X x i y i = 365027 . SS xy = X x i y i - ( x i )( y i ) n = 365027 - 548 × 5782 12 = 100982 . 33 SS xx = X x 2 i - ( x i ) 2 n = 34978 - 548 2 12 = 9952 . 67 b 1 = SS xy SS xx = 100982 . 33 9952 . 67 = 10 . 14626( 10 . 146) b 0 = ¯ y - b 1 ¯ x = 5782 12 - 10 . 14626 × 548 12 = 18 . 488 (b) b 1 (= 10 . 146) is the estimated increase in mean labor cost for every 1 unit increase in the batch size. b 0 (= 18 . 488) is the estimated mean labor cost when batch size = 0; no. (c) ˆ y = 18 . 488 + 10 . 146 x (d) ˆ y = 18 . 488 + 10 . 146 × 60 = 627 . 25 is both a point estimate of the mean direct labor cost for all batches of size 60 and a point prediction of the direct labor cost for an individual batch of size 60. II . Problem 10.30 (p.407) of the textbook. Solution : s 2 = SSE n - 2 = 896 . 8 10 - 2 = 112 . 1 s = s 2 = 112 . 1 = 10 . 588

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ISOM 111 L6-L7, Fall 2009 2 III . Problem 10.36 (p.411-413) of the textbook, questions a - h , and k – Using the appropriate data set and s from the computer output, with the help of a hand calculator , calculate SS xx and s b 1 .
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hwk6_sol - ISOM 111 L6-L7 Fall 2009 1 Homework 6 Solutions...

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