chapter13.3_13.5_slides

chapter13.3_13.5_slides - 12/1/2009 Many aspects of the...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
12/1/2009 1 Many aspects of the simple harmonic motion can be understood by analyzing the uniform circular motion Consider an object doing a uniform circular motion - radius is A - tangential speed is v 0 (constant) The x-component of the tangential velocity (absolute value) ) sin( 0 v v x A x A 2 2 ) sin( x v 2 2 0 x A A v v x C=v 0 /A is a constant. Speed of an object doing simple harmonic motion: here . There is clear similarity between the x-component of the velocity of a uniform circular motion and the velocity of the simple harmonic motion. ( flash animation ) 2 2 2 2 0 x A C x A A v v x x v ) ( ) ( 2 2 2 2 x A C x A m k v m k C
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
2 Period of uniform circular motion: For simple harmonic motion, the maximum speed v 0 and vibration amplitude A is related by (energy conservation) Substituting v 0 into (1) k m T 2 A m k v 0 2 2 0 2 1 2 1 kA mv ) 1 ( 2 0 v A speed tangential nce circumfere T k m A m k A v A T 2 2 2 0 Period is independen t of vibration amplitude (flash demo) Frequency: (number of cycles/second) - Unit: 1/second or Hertz, Hz The angular frequency k ƒ 2
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/02/2010 for the course PHY 101 taught by Professor Pralle during the Spring '08 term at SUNY Buffalo.

Page1 / 8

chapter13.3_13.5_slides - 12/1/2009 Many aspects of the...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online