Lec-36-Chap19-6-Complete

Lec-36-Chap19-6-Complete - Lec-36-Chap19-6-Complete...

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Lec-36-Chap19-6-Complete 11/30/2009 Electrolysis 1 Lec-36: Electrochemistry and its Applications Chapter 19 1 2 For a voltaic cell with reaction   22 11 electr ox r ons red ox exch g e e d an d n             2 2 | || Pt s ox , red red , ox | Pt s For example         1 red 0 red 1 1 1 1 1 Reduction: ox red red 0.0592V ox / red ox / red log ox EE n e E n          2 red 0 ox 2 2 2 2 2 Oxidation red ox we write as a reduction ox red red 0.0592V ox / red ox / red log ox e E ne n n 
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Lec-36-Chap19-6-Complete 11/30/2009 Electrolysis 2 3 anode cell cell cathode red r red ox ed E E E E E E  For a voltaic cell with reaction   22 11 electr ox r ons red ox exch g e e d an d n                 2 1 0 1 cell 0 ce 2 ll ox / red red ox / red 0.059 ox / red ox 2 ox / red l r V ox og ed E E n E E E E 4 What is the emf of the voltaic cell             0 2 0 2 mol mol Co s CoCl 0.10 NiCl 1.00 Ni s LL Co / Co s 0.28V ; Ni / Ni s 0.25V EE      ? A. 0.310 V B. 0.053 V C. 0.060 V D. 0.310 V E. 0.030 V ANS: C
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Lec-36-Chap19-6-Complete 11/30/2009 Electrolysis 3 5 What is the correct form of writing the voltaic cell when             22 0 2 0 2 mol mol CoCl 1.00 ; NiCl 0.01 LL Co / Co s 0.28V ; Ni / Ni s 0.25V EE       ?         mol mol A: Co s CoCl 1.00 NiCl 0.01 Ni s mol mol B: Ni s NiCl 0.01 CoCl 1.00 Co s Answer: B                   2 2 3 3 2 2 red anode ox 3 2 3 2 2 3 0.0V 2H O H g,1bar 2H O aq, 2 2H O aq, 2 2H O H g,1bar 0.0592 As a reductio V 1 H O / H H O / H lo n g 2 HO x x x Ce E E E E    Measurement of pH Consider the following electrochemical cell             3 23 acid solution of unknown concentration standard 2 standard hydrogen electrode Pt s |H g,1bar |H O aq, aq,C |H g,1bar |Pt C s || x 6
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Lec-36-Chap19-6-Complete 11/30/2009 Electrolysis 4           cell cathode anode red red cell red ox 2
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Lec-36-Chap19-6-Complete - Lec-36-Chap19-6-Complete...

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