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9-15-09

# 9-15-09 - Biology 330 Class Notes ARTICLE Dinosaurs were...

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Biology 330 – Class Notes – 9/15/09 ARTICLE: Dinosaurs were Type I survivorship curve Life table was created for extinct dinosaurs 22, 26, 28 were the average ages at death Poa annua - example Age Nx Ix Dx Mx Lx Tx 0 843 1.000 121 0.144 782.5 6607.5 3 722 0.846 105 0.27 624.5 4260 Poa annua (con’t) Bx = average number of individuals produced at that particular age Age Ix Bx Ixbx X*lx*bx 0 1.000 0 0 0 3 0.857 3000 256.8 770.4 6 0.625 620 387.5 2325.0 9 0.375 430 161.25 1451.25 12 0.171 210 35.91 430.92 15 0.064 60 3.84 57.60 18 0.018 30 0.54 9.72 21 0.004 10 0.04 0.84 24 0.000 - - - Sum = Sum = 845.88 Anticipated reproductive output if we started with a single individual In the life of this particular (single) individual, it will produce 845 . 88 In a typical Sum = 5045.73

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offspring life, the numbers for each age represent the number of individuals produced at each age Garcia article – fitness is a function of not only reproductive output, but also the likeiihood of reaching the age necessary to achieve that reproductive output. Fitness likelihood of reaching a reproductive age AND the reproductive output AT THAT AGE. so if the likelihood of reaching that reproductive age is low, it doesn’t matter how much reporudtive output takes place Nt = N0*e^(r*t) Calculate r (the rate of growth) One generation = capital “t” (T) T = generation time = the length of time between the birth date of the parent and the birth date of the average offspring We need a way to weight average generation time o R0 = net reproductive rate = Sum( lx * bx ) o T = generation time = [Sum( x* lx * bx ) / Sum( lx * bx )] Poa annua example: 845.88 = 1*e^(r*T) T = 5.97 months the average time at which reproduction takes place This average assumes all the individuals wait until 5.97 months (age) to have all the offspring that is produced over the life of the individual (in this case, 845.88). So all individuals are born at 5.97 months (based on the average) T = generation time = [Sum( x* lx * bx ) / Sum( lx * bx )] = 5045.73 / 845.88 = 5.97 845.88 = 1*e^(r*T) ln(R0)/T = r ln(R0) / r = T Nt = N0*e^(r*t) lx = the probability of making it to any particular age Given nx and bx
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9-15-09 - Biology 330 Class Notes ARTICLE Dinosaurs were...

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