NewtonRaphson

# NewtonRaphson - 2.3-13.16 Solution 4.7 2.4-14.23 Error...

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1.5 2 2.5 3 3.5 4 4.5 5 5.5 -100 -80 -60 -40 -20 0 20 40 60 80 y = f(x) y = f(x) x y

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1.5 2 2.5 3 3.5 4 4.5 5 5.5 -100 -80 -60 -40 -20 0 20 40 60 80 y = f(x) y = f(x)
Solution of the equation: f(x) = exp(x)*sin(2*x)-3.25 = 0 using the Newton-Raphson method in the range (2,5). First we create a table using Excel: Parameters for the Newton-Raphson solution: x y = f(x) epsilon: 0 2 -8.84 Nmax: 1000 2.1 -10.37 x0: 5 2.2 -11.84
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Unformatted text preview: 2.3-13.16 Solution: 4.7 2.4-14.23 Error: 2.5-14.93 2.6-15.14 2.7-14.75 2.8-13.63 2.9-11.69 3-8.86 3.1-5.09 3.2-0.39 3.3 5.2 3.4 11.56 3.5 18.51 3.6 25.8 3.7 33.1 3.8 40.02 3.9 46.08 4 50.77 4.1 53.51 4.2 53.74 4.3 50.87 4.4 44.39 4.5 33.85 4.6 18.92 4.7-0.53 4.8-24.43 4.9-52.46 5-83.99 Solve for x...
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## This note was uploaded on 01/08/2010 for the course COT 3502 taught by Professor Hawkins during the Fall '08 term at University of Florida.

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NewtonRaphson - 2.3-13.16 Solution 4.7 2.4-14.23 Error...

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