NewtonRaphsonFancy

NewtonRaphsonFancy - -0.39 3.30 5.20 3.40 11.56 3.50 18.51...

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Solution of the equation: f(x) = exp(x)*sin(2*x)-3.25 = 0 using the Newton-Raphson method in the range (2,5). First we create a table using Excel: Parameters for the Newton-Raphson solution: x y = f(x) epsilon: 0 2.00 -8.84 Nmax: 1000 2.10 -10.37 x0: 5.0000 2.20 -11.84 2.30 -13.16 Solution: 4.7 2.40 -14.23 Error: 0 2.50 -14.93 2.60 -15.14 2.70 -14.75 2.80 -13.63 2.90 -11.69 3.00 -8.86 3.10 -5.09 3.20
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Unformatted text preview: -0.39 3.30 5.20 3.40 11.56 3.50 18.51 3.60 25.80 3.70 33.10 3.80 40.02 3.90 46.08 4.00 50.77 4.10 53.51 4.20 53.74 4.30 50.87 4.40 44.39 4.50 33.85 4.60 18.92 4.70-0.53 4.80-24.43 4.90-52.46 5.00-83.99 1.50 2.00-100.00-80.00-60.00-40.00-20.00 0.00 20.00 40.00 60.00 80.00 y Solve for x 2.50 3.00 3.50 4.00 4.50 5.00 5.50 y = f(x x...
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NewtonRaphsonFancy - -0.39 3.30 5.20 3.40 11.56 3.50 18.51...

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