Sheet (1) Solution

# Sheet (1) Solution - 1 Math 103 Class Work Sheet (1)...

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Unformatted text preview: 1 Math 103 Class Work Sheet (1) Solution 1. (i)   3 1 ) ( 2    x x f Domain is R Range is 3  y 2 ) ( x x f  2 ) 1 ( ) (   x x f Shifts right by 1 step   3 1 ) ( 2    x x f Shifts up by 3 steps (ii) 3 2 ) (   x x f Domain is R Range is R x x f  ) ( x x f 2 ) (  3 2 ) (   x x f Shifts up by 3 steps (iii) 1 ) 1 ( 2 ) ( 2 2      x x x x f Domain is R Range is 1   y 2 ) ( x x f  2 ) 1 ( ) (   x x f Shifts left by 1 step 1 ) 1 ( ) ( 2    x x f Shifts down by 1 step 2 (iv) 1 ) 2 ( 3 ) ( 2    x x f Domain is R Range is 1   y 2 ) ( x x f  2 ) 2 ( 3 ) (   x x f Shifts left by 2 steps 1 ) 2 ( 3 ) ( 2    x x f Shifts down by 1 step (v) 2 3 ) (   x x f Domain is } 2 {   R Range is } {  R x x f 1 ) (  2 3 ) (   x x f Shifts left by 2 steps (vi) 2 ) 1 ( 1 ) ( 2     x x f Domain is } 1 {  R Range is 2  y 2 1 ) ( x x f  2 ) 1 ( 1 ) (   x x f Shifts right by 1 step 2 ) 1 ( 1 ) (    x x f Reflection on x-axis 2 ) 1 ( 1 ) ( 2     x x f Shifts up by 2 steps 3 2. (i)        2 sin x y Period is   4 2 1 2  (ii) | ) 2 cos( | x y    For ) 2 cos( x y    , period is 1 2 2    Period of | ) 2 cos( | x y    2 1  from the graph (iii)         2 sin  x y Period is  2 (iv) 1 4 cos           x y Period is  2 (v)           2 2 sin ) 2 sin(   x x y Period is    2 2 4 3. (i) 2 2 3 1 2 3 . 2 1 2 1 . 2 1 3 sin 4 cos 3 cos 4 sin 3 4 sin 12 7 sin                                                    (ii)                                       ...
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## This note was uploaded on 01/09/2010 for the course MATH Math103 taught by Professor Dr.prof.mostafaamer during the Spring '09 term at German University in Cairo.

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Sheet (1) Solution - 1 Math 103 Class Work Sheet (1)...

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