10162009 - Nomenclature of Alkenes Based on the same rules...

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CH 310M/318M – MWF 12:00 – Lecture 22 – F 10/16/2009 Reading Assignment : Sections 6.1, 6.3A (1 st reading for Exam #3) Graded Homework : HW#12 deadline = 3:00 p.m. on Mon 10/19 Last Time : Structural factors that influence acid/base strength (continued…) Acid-base chemistry in the resolution of enantiomers Textbook Problems : 5.1-5.20, 5.23, 5.24, 5.30b, 5.32, 5.33b,c, 5.34a,b,c, 5.35 Today : Structure, nomenclature, and stereochemistry of alkenes Midterm Exam #2 is scheduled for Thu 10/22 from 7:00 to 9:00 p.m. Detailed information about the exam (room assignments, coverage, ground rules, review checklist, etc.) will be posted in Blackboard sometime this weekend, and will be discussed in lecture on Monday… Students who signed up to take the conflict exam will receive e-mail sometime Monday afternoon/evening with further instructions…
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Unformatted text preview: Nomenclature of Alkenes Based on the same rules we used for naming alkanes, with some adjustments 1) The parent chain is the longest continuous chain that contains the most double bonds. THIS MAY NOT BE THE SAME AS THE LONGEST CONTINUOUS CHAIN THAT CONTAINS THE MOST C ATOMS!!! 2) Number the parent chain to give the first double bond encountered the lowest number possible. Position(s) of double bond(s) precedes root in name. 3) As usual, indicate positions of substituents with numbers 4) ane suffix changes to ene suffix. If more than one double bond is present in the parent chain, use a modifer such as di, tri, tetra, etc. to indicate the total number of double bonds in the parent chain....
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This note was uploaded on 01/08/2010 for the course CH 53675 taught by Professor Bocknack during the Fall '09 term at University of Texas at Austin.

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10162009 - Nomenclature of Alkenes Based on the same rules...

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