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# solution_11pdf - yoon(jy4326 HW11 markert(58840 This...

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yoon (jy4326) – HW11 – markert – (58840) 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 3) 10.0 points A block of unknown mass is attached to a spring of spring constant 5 . 3 N / m and under- goes simple harmonic motion with an ampli- tude of 15 cm. When the mass is halfway between its equilibrium position and the end- point, its speed is measured to be 20 . 8 cm / s. Calculate the mass of the block. Correct answer: 2 . 06725 kg. Explanation: Let : k = 5 . 3 N / m , A = 15 cm , and v = 20 . 8 cm / s . If the maximum displacement (amplitude) is A , the halfway displacement is A 2 . By energy conservation, K i + U i = F f + U f 0 + 1 2 k A 2 = 1 2 m v 2 + 1 2 k parenleftbigg A 2 parenrightbigg 2 k A 2 = m v 2 + 1 4 k A 2 m = 3 k A 2 4 v 2 = 3 (5 . 3 N / m) (0 . 15 m) 2 4 (0 . 208 m / s) 2 = 2 . 06725 kg . 002 (part 2 of 3) 10.0 points Find the period of the motion. Correct answer: 3 . 92409 s. Explanation: ω = radicalbigg k m = radicalBigg 5 . 3 N / m 2 . 06725 kg = 1 . 60118 rad / s , so the period is T = 2 π ω = 2 π 1 . 60118 rad / s = 3 . 92409 s .

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solution_11pdf - yoon(jy4326 HW11 markert(58840 This...

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