{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Homework 7 Solution

Homework 7 Solution - Version PREVIEW Homework 7...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Version PREVIEW – Homework 7 – Savrasov – (39825) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. Celsius vs Fahrenheit 001 10.0 points The coldest temperature possible is - 273 de- grees Celsius, which is called absolute zero. What is this temperature in degrees Fahrenheit? 1. +491 . 4 F 2. - 523 . 4 F 3. - 459 . 4 F correct 4. +459 . 4 F 5. - 491 . 4 F 6. 32 F 7. +523 . 4 F 8. - 32 F 9. 0 F 10. - 119 . 667 F Explanation: Let : T C = - 273 C . T F = 9 5 T C + 32 = 9 5 ( - 273 C) + 32 = - 459 . 4 F . Pendulum Changes Length 002 10.0 points A clock has a 1 m bronze pendulum which is accurate at a temperature of 23 C. g m 1 m a r a t a φ θ What is the change in the length of the pendulum when the temperature reaches 43 . 7422 C? (The linear expansion coefficient of bronze is 1 . 9 × 10 7 ( C) 1 .) Correct answer: 0 . 00394102 mm. Explanation: Given : L 1 = 1 m , T 1 = 23 C , T 2 = 43 . 7422 C , and α = 1 . 9 × 10 7 ( C) 1 . We have this formula to calculate the expan- sion Δ L = α L 1 Δ T = α L 1 ( T 2 - T 1 ) = bracketleftbig 1 . 9 × 10 7 ( C) 1 bracketrightbig (1 m) (20 . 7422 C) × parenleftbigg 1000 mm 1m parenrightbigg = 0 . 00394102 mm .
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern