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Unformatted text preview: Version PREVIEW – Homework 6 – Savrasov – (39825) 1 This printout should have 10 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. Serway CP 24 29 001 10.0 points Heliumneon laser light of wavelength 650 . 2 nm is sent through a 0 . 259 mm wide single slit. What is the width of the central maximum on a screen 1 . 2 m from the slit? Correct answer: 6 . 02502 mm. Explanation: Given : λ = 650 . 2 nm = 6 . 502 × 10 − 7 m , L = 1 . 2 m , and a = 0 . 259 mm = 0 . 000259 m . y L θ We use the fact that for small θ . tan θ ≈ sin θ . tan θ = y L , and sin θ = λ a For small θ , tan θ = sin θ , so y L = λ a , and since the width x of the central maximum is equal to 2 y , x = 2 y = 2 λ L a = 2 (6 . 502 × 10 − 7 m) (1 . 2 m) . 000259 m · 1000 mm 1 m = 6 . 02502 mm . Serway CP 24 31 002 (part 1 of 2) 10.0 points Light of wavelength 477 . 2 nm illuminates a single slit of width 0 . 62 mm. At what distance L from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0 . 85 mm from the central maximum? Correct answer: 1 . 10436 m. Explanation: Given : λ = 477 . 2 nm , y = 0 . 85 mm , and a = 0 . 62 mm . y L a S 1 S 2 θ viewing screen Since sin θ = y m L = m λ a , for the first minimum ( m = 1), L = a y λ = (0 . 00062 m) (0 . 00085 m) 4 . 772 × 10 − 7 m = 1 . 10436 m . Version PREVIEW – Homework 6 – Savrasov – (39825) 2 003 (part 2 of 2) 10.0 points What is the width of the central maximum?...
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 Fall '09
 RichardScalettar
 Work, Light, Wavelength, Correct Answer, θ= Tipler

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