{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW1c - GenericStudent – Homework 1 – savrasov – 39823...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: GenericStudent – Homework 1 – savrasov – 39823 – Jan 02, 2008 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 2 points Four point charges are placed at the four cor- ners of a square. Each side of the square has a length L . q 1 =- q q 3 = q q 2 = q q 4 = q P L L Find the magnitude of the electric force on q 2 due to all three charges q 1 , q 3 and q 4 . Given L = 1 m and q = 1 . 92 μ C. Correct answer: 0 . 0496976 N. Explanation: F 1 F 4y F 4 F 3 F 4x q 2 From the above figure, we see that F 1 =- k q 2 L 2 ˆ ı =- ( 8 . 98755 × 10 9 N · m 2 / C 2 ) × (1 . 92 × 10- 6 C) 2 (1 m) 2 =- . 0331317 N F 3 =- k q 2 L 2 ˆ =- ( 8 . 98755 × 10 9 N · m 2 / C 2 ) × (1 . 92 × 10- 6 C) 2 (1 m) 2 =- . 0331317 N F 4 x = k q 2 2 L 2 1 √ 2 = 8 . 98755 × 10 9 N · m 2 / C 2 2 · (1 m) 2 × (1 . 92 × 10- 6 C) 2 √ 2 = 0 . 0117138 N F 4 y =- k q 2 2 L 2 1 √ 2 =- 8 . 98755 × 10 9 N · m 2 / C 2 2 · (1 m) 2 × (1 . 92 × 10- 6 C) 2 √ 2 =- . 0117138 N k ~ F k 2 = ( F 1 + F 4 x ) 2 + ( F 3 + F 4 y ) 2 = (- . 0331317 N + 0 . 0117138 N) 2 + (- . 0331317 N +- . 0117138 N) 2 so that k ~ F k = √ . 00246985 N 2 = . 0496976 N . keywords: 002 (part 1 of 1) 2 points Three identical point charges, each of mass 110 g and charge + q , hang from three strings, as in the figure. The acceleration of gravity is 9 . 8 m / s 2 , and the Coulomb constant is 8 . 98755 × 10 9 N · m 2 / C 2 . 9 . 8 m / s 2 1 . 5 c m 110 g + q 1 . 5 c m 110 g + q 49 ◦ 110 g + q If the lengths of the left and right strings are each 10 . 5 cm, and each forms an angle of 49 ◦ with the vertical, determine the value of q . Correct answer: 0 . 832571 μ C. Explanation: Let : θ = 49 ◦ , GenericStudent – Homework 1 – savrasov – 39823 – Jan 02, 2008 2 m = 110 g = 0 . 11 kg , L = 10 . 5 cm = 0 . 105 m , g = 9 . 8 m / s 2 , and k e = 8 . 98755 × 10 9 N · m 2 / C 2 ....
View Full Document

{[ snackBarMessage ]}

Page1 / 5

HW1c - GenericStudent – Homework 1 – savrasov – 39823...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon bookmark
Ask a homework question - tutors are online