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# HW2c - GenericStudent Homework 2 savrasov 39823 This...

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GenericStudent – Homework 2 – savrasov – 39823 – Jan 02, 2008 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 2 points An electric field of magnitude 23000 N / C and directed upward perpendicular to the Earth’s surface exists on a day when a thunderstorm is brewing. A truck that can be approximated as a rectangle 5 . 9 m by 1 . 3 m is traveling along a road that is inclined 11 relative to the ground. Determine the electric flux through the bot- tom of the truck. Correct answer: 173169 N · m 2 / C. Explanation: Let : E = 23000 N / C , = 5 . 9 m , w = 1 . 3 m , and θ = 11 . By Gauss’ law, Φ = ~ E · ~ A The flux through the bottom of the car is Φ = E A cos θ = E ‘ w cos θ = (23000 N / C) (5 . 9 m) × (1 . 3 m) cos(11 ) = 173169 N · m 2 / C . keywords: 002 (part 1 of 1) 2 points A ring of radius 8 cm that lies in the yz plane carries positive charge of 7 μ C uniformly distributed over its length. A particle of mass m that carries a charge of - 7 μ C oscillates about the center of the ring with an angular frequency of 14 rad / s.

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HW2c - GenericStudent Homework 2 savrasov 39823 This...

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