HW3solution08

HW3solution08 - Version PREVIEW HW 3 Savrasov(39824 This...

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Version PREVIEW – HW 3 – Savrasov – (39824) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. Wavelength Comparison 001 10.0 points The speed oF light is 2 . 998 × 10 8 m / s. The ratio oF the wavelength oF visible light oF wavelength 600 nm to that oF an ±M radio wave oF Frequency 100 MHz is about 1. 10 1 2. 10 7 correct 3. 10 3 4. 10 14 5. 10 10 Explanation: The wavelength oF the ±M radio wave is λ FM = c f FM = 2 . 998 × 10 8 m / s 100 MHz = 2 . 998 m . Then the ratio oF the wavelength oF visible light to that oF the ±M radio wave is about 1 × 10 7 . keywords: Perpendicular Mirrors 002 (part 1 oF 2) 10.0 points Consider the case in which light ray A is in- cident on mirror 1 , as shown in the fgure. The re²ected ray is incident on mirror 2 and subsequently re²ected as ray B. Let the an- gle oF incidence (with respect to the normal) on mirror 1 be θ A = 50 and the point oF incidence be located 20 cm From the edge oF contact between the two mirrors. 90 x A B mirror 1 mirror 2 θ A θ B What is the angle oF the re²ection oF ray B (with respect to the normal) on mirror 2 ? Correct answer: 40 . Explanation: IF the angle oF the incident ray A is θ A , the angle oF re²ection must also be θ A . Since the mirrors are perpendicular to each other, angle θ B is equal to 90 - θ A θ B = 90 - θ A = 90 - 50 = 40 . 003 (part 2 oF 2) 10.0 points Determine the angle between the rays A and B. 1. 50 2. 0 3. 80 4. 40 5. 180 correct 6. 100 7. 90 Explanation: ReFer to the fgure below. Consider the angle each ray makes with mirror 1 . Ray A
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Version PREVIEW – HW 3 – Savrasov – (39824) 2 makes an angle of φ A with
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HW3solution08 - Version PREVIEW HW 3 Savrasov(39824 This...

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