HW5a - Version One Homework 5 savrasov 39822 Oct 31, 2007...

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Version One – Homework 5 – savrasov – 39822 – Oct 31, 2007 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. Climbing a Rope 08:01, trigonometry, numeric, > 1 min, nor- mal. 001 (part 1 oF 1) 2 points Tim, with mass 60 kg, climbs a gymnasium rope a distance oF 3 . 5 m. The acceleration oF gravity is 9 . 8 m / s 2 . How much potential energy does Tim gain? Correct answer: 2058 J. Explanation: Let : m = 60 kg , h = 3 . 5 m , and g = 9 . 8 m / s 2 . Potential energy is U = m g h = (60 kg) (9 . 8 m / s 2 ) (3 . 5 m) = 2058 J . keywords: Lifting a Bowling Ball 08:01, trigonometry, numeric, > 1 min, nor- mal. 002 (part 1 oF 1) 2 points A 6 . 4 kg bowling ball is liFted 2 . 1 m into a storage rack. The acceleration oF gravity is 9 . 8 m / s 2 . Calculate the increase in the ball’s potential energy. Correct answer: 131
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HW5a - Version One Homework 5 savrasov 39822 Oct 31, 2007...

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