HW6c - GenericStudent – Homework 6 – savrasov – 39823...

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Unformatted text preview: GenericStudent – Homework 6 – savrasov – 39823 – Jan 02, 2008 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 1 points After a 3 . 91 Ω resistor is connected across a battery with a 0 . 24 Ω internal resistance, the electric potential between the physical battery terminals is 7 V. What is the rated emf of the battery? Correct answer: 7 . 42967 V. Explanation: Let : R = 3 . 91 Ω , r = 0 . 24 Ω , and V = 7 V . The current drawn by the external resistor is given by I = V R = 7 V 3 . 91 Ω = 1 . 79028 A . The output voltage is reduced by the inter- nal resistance of the battery by V = E - I r , so the electromotive force is E = V + I r = 7 V + (1 . 79028 A) (0 . 24 Ω) = 7 . 42967 V . keywords: 002 (part 1 of 4) 1 points A 35 Ω lamp and a 74 Ω lamp are connected in series and placed across a potential of 42 V. What is the equivalent resistance of the circuit? Correct answer: 109 Ω. Explanation: Let : R 1 = 35 Ω , R 2 = 74 Ω , and V = 42 V . The equivalent resistance of the circuit is R = R 1 + R 2 = 35 Ω + 74 Ω = 109 Ω . 003 (part 2 of 4) 1 points What is the current in the circuit?...
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This note was uploaded on 01/10/2010 for the course PHY na taught by Professor Richardscalettar during the Winter '09 term at UC Davis.

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HW6c - GenericStudent – Homework 6 – savrasov – 39823...

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