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# HW7c - GenericStudent Homework 7 savrasov 39823 This...

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GenericStudent – Homework 7 – savrasov – 39823 – Jan 02, 2008 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 2 points An electron in a vacuum is first accelerated by a voltage of 46000 V and then enters a region in which there is a uniform magnetic field of 0 . 122 T at right angles to the direction of the electron’s motion. What is the force on the electron due to the magnetic field? Correct answer: 2 . 48642 × 10 - 12 N. Explanation: Let : V = 1 . 27205 × 10 8 m / s and B = 0 . 122 T . The kinetic energy gained after acceleration is KE = 1 2 m e v 2 = q e V , so the velocity is v = r 2 q e V m = s 2(1 . 60218 × 10 - 19 C)(46000 V) 9 . 10939 × 10 - 31 kg = 1 . 27205 × 10 8 m / s . Then the force on it is f = qvB = (1 . 60218 × 10 - 19 C) × (1 . 27205 × 10 8 m / s)(0 . 122 T) = 2 . 48642 × 10 - 12 N . keywords: 002 (part 1 of 1) 2 points A rectangular loop of wire carrying a current of 1 . 4 A is suspended vertically and attached to the right arm of a balance. After the system is balanced, an external magnetic field, ~ B , is introduced. The field threads the lower end

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