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HW9solution08 - Version PREVIEW HW 9(last to do...

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Version PREVIEW – HW 9 (last to do) – Savrasov – (39824) 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. Expanding Gas 01 001 10.0 points Given: R = 8 . 31 J / K / mol , 5 mol of an ideal gas is kept at 559 C in an expansion from 1 L to 5 L . How much work is done by the gas? Correct answer: 55637 . 6 J. Explanation: Let : n = 5 mol , R = 8 . 31 J / K / mol , T = 559 C = 832 K , V f = 5 L , and V i = 1 L . In an isothermal process, the work done by an ideal gas is W = nRT ln parenleftbigg V f V i parenrightbigg = (5 mol) (8 . 31 J / K / mol) (832 K) × ln parenleftbigg 5 L 1 L parenrightbigg = 55637 . 6 J . Isothermal compression 002 (part 1 of 3) 10.0 points Given: R = 8 . 31451 J / K · mol . Two moles of helium gas initially at 380 K and 0 . 63 atm are compressed isothermally to 1 . 05 atm. Find the final volume of the gas. Assume the helium to behave as an ideal gas. Correct answer: 0 . 0594089 m 3 . Explanation: Given : n = 2 mol , R = 8 . 31451 J / K · mol , T f = 380 K , and P f = 1 . 05 atm . From the ideal gas law, P f V f = nRT V f = nRT P f = (2 mol)(8 . 31451 J / K · mol)(380 K) (1 . 05 atm)(1 . 013 × 10 5 Pa / atm) = 0 . 0594089 m 3 .
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