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QUIZ 3
Solution:
The ball does not accelerate along x axis. Therefore
v
x
(t)=v*cos(
α
)
and
x(t)=v*t*cos(
).
It travels distance
L=22
m and the time to reach the wall is
t
0
=L/[v*cos(
)]=22/(25*cos(40))=1.15 s.
The ycomponent of the velocity and coordinate are
v
y
(t)=v*sin(
)gt and y(t)=v*t*sin(
)0.5gt
2
.
Since we know the travel time, we can find the ball’s ycoordinate:
y(t
0
)=v* t
0
*sin(
)0.5g t
0
2
=25*1.15*sin(40)0.5*10*1.15*1.15=
=18.486.61=11.87~12 m
(a) The vertical distance above the release point is 12 m
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This note was uploaded on 01/10/2010 for the course PHY na taught by Professor Richardscalettar during the Fall '09 term at UC Davis.
 Fall '09
 RichardScalettar

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