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Unformatted text preview: Version PREVIEW – Test Homework – Savrasov – (39825) 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. Barge in Fresh Water 001 (part 1 of 2) 10.0 points A loaded flatbottom barge floats in fresh wa ter. The bottom of the barge is 3 . 06 m below the water line. When the barge is empty the barge’s bottom is only 2 . 23 m below the water line. What is the difference between the pressure on the bottom of the loaded barge and the pressure at the water line? Correct answer: 29988 Pa. Explanation: Let : d 1 = 3 . 06 m and ρ = 1000 kg / m 3 . P = d 1 ρ g = 3 . 06 m (1000 kg / m 3 ) (9 . 8 m / s 2 ) = 29988 Pa . 002 (part 2 of 2) 10.0 points If the surface area of the bottom of the barge is 559 m 2 what is the weight of the load in the barge? Correct answer: 4 . 54691 × 10 6 N. Explanation: Let : d 2 = 2 . 23 m and a 1 = 559 m 2 . Weight in a bouyant, stable system is equal to the mass of the fluid displaced times grav ity. This is known as Archimedes’ Principle. The mass of water displaced, and thus the mass of the load, is W = mg = ρ ( d 1 − d 2 ) a 1 g = (1000 kg / m 3 ) (3 . 06 m − 2 . 23 m) · (559 m 2 ) (9 . 8 m / s 2 ) = 4 . 54691 × 10 6 N . Bernoulli Principle 003 (part 1 of 4) 10.0 points Shown below is a crosssection of a verti cal view of a pipe discharging a fluid into the atmosphere at its highest elevation. The pipe diameter increases and then remains con stant. P i is the pressure and bardbl vectorv i bardbl is the speed of the fluid, at locations i = y , x , z , and u . y x z u If the fluid is incompressable and nonvis cous, what is the relationship between the magnitude of the velocity v ≡ bardbl vectorv bardbl at position y and x ? 1. bardbl vectorv x bardbl = bardbl vectorv y bardbl 2. bardbl vectorv x bardbl < bardbl vectorv y bardbl correct 3. Indeterminable; not enough information is available....
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 Fall '09
 RichardScalettar
 Force, Work

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