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Unformatted text preview: i 2 in the anti-clockwise direction (the sign is negative). The equation for the other loop is this: 10 i 2 + 4 i 2 + 5( i 2-i 1 ) = 0 . It is zero because there is no source in that loop. Again, through 5 H we have the current i 2 in the clockwise direction and i 1 in the anti-clockwise direction. Once you have this system, you can solve it in the usual way by taking the Laplace transform. 1...
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This note was uploaded on 01/12/2010 for the course MATH 421 taught by Professor Nataliakomarova during the Winter '07 term at San Jose State University .
- Winter '07