Quiz3Solutions

Quiz3Solutions - Newberger Math 247 Spring 03 Solutions for...

This preview shows pages 1–2. Sign up to view the full content.

Solutions for Quiz 1.5 and 1.7 A = 1 2 - 1 - 2 8 - 10 5 - 4 9 5 2 3 b = 0 - 12 14 8 1. (a) (8 points) Solve the system A x = b where A and b are given above. Put your answer in parametric vector form. To solve, reduce the augmented matrix. 1 2 - 1 0 - 2 8 - 10 - 12 5 - 4 9 14 5 2 3 8 1 2 - 1 0 0 12 - 12 - 12 0 - 14 14 14 1 - 8 8 8 1 2 - 1 0 0 1 - 1 - 1 0 0 0 0 0 0 0 0 1 0 1 2 0 1 - 1 - 1 0 0 0 0 0 0 0 0 Note that there are three columns, so the vector x is in R 3 . x = x 1 x 2 x 3 = 2 - x 3 - 1 + x 3 x 3 = 2 - 1 0 + - 1 1 1 x 3 (b) (4 points) Give a geometric description of the solution set that you found in part (a). The solution set to this matrix equation is a line in R 3 passing through the vector 2 - 1 0 parallel to the span of the vector

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/12/2010 for the course MATH 247 taught by Professor F,newberger during the Spring '03 term at Stanford.

Page1 / 2

Quiz3Solutions - Newberger Math 247 Spring 03 Solutions for...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online