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Unformatted text preview: a and b such that a + b3 ab 2 b + 1 = . This means is not in H and H is not a subspace. 2. (12 points) Show that the following set is not a subspace of R 2 . W = ( x y x y x ) Here is a graph of the region W . W uu Note that the vector u = (1 , 0) is in W , since1 1 . Howeveru = (1 , 0) is not in W , since 1 1 is false. Thus W is not closed under scalar multiplication....
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This note was uploaded on 01/12/2010 for the course MATH 247 taught by Professor F,newberger during the Spring '03 term at Stanford.
 Spring '03
 F,newberger
 Math

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