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# CS201-04 - Introduction to Programming Lecture 4 Key Words...

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Unformatted text preview: Introduction to Programming Lecture 4 Key Words of C main if else while do for x = 2 + 4 ; x = 6 ; 6 Memory Memory x = a + b ; a b x #include <iostream.h> main ( ) { int age1, age2, age3, age4, age5, age6, age7, age8, age9, age10 ; int TotalAge ; int AverageAge ; cout << “ Please enter the age of student 1: “ ; cin >> age1 ; cout << “ Please enter the age of student 2: “ ; cin >> age2 ; : : TotalAge = age1+ age2 + age3+ age4+ age5+age6+ age7+ age8+age9 + age10 ; AverageAge = TotalAge / 10 ; } cout<< “The average age of the class is :” << AverageAge ; Quadratic Equation In algebra y = ax2 + bx + c In C y = a*x*x + b*x + c a*b%c +d a*(b%c) = a*b%c ? Discriminant b2 - 2a 4c = b*b - 4*a*c /2 *a answer Solution = (b*b - 4*a*c) /(2 *a) Correct answer Incorrect No expression on the left hand side of the assignment Integer division truncates fractional part Liberal use of brackets/parenthesis Interesting Problem Given a four­digit integer, separate and print the digits on the screen Analysis Number = 1234 Take the remainder of the above number after dividing by 10 Eg 1234 / 10 gives remainder 4 1234 % 10 = 4 Remove last digit – 1234/10 = 123.4 (Truncation due to Integer Division) – 123 123 %10 gives 3 Remove last digit – 123/10 = 12.3 (Truncation due to Integer Division) – 12 12 % 10 gives remainder 2 Remove last digit – 12/10 = 1.2 (Truncation due to Integer Division) –1 Final digit remains #include <iostream.h> main ( ) { int number; int digit; cout << “Please enter a 4 digit integer : ”; cin >> number; digit = number %10; cout <<“The digit is: “ << digit << ‘\n’; // first digit; and then << ‘\n’ number = number / 10; digit = number % 10; cout <<“The digit is: “ << digit << ‘\n’; number = number / 10; digit = number % 10; cout <<“The digit is: “ << digit << ‘\n’; number = number / 10; digit = number % 10; cout <<“The digit is: “ << digit; } Code Special Character Newline \n ...
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