(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6) }
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Let E be the event "sum equal to 1". There are no outcomes which correspond to
a sum equal to 1, hence
P(E) = n(E) / n(S) = 0 / 36 = 0
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b) Three possible ouctcomes give a sum equal to 4: E = {(1,3),(2,2),(3,1)}, hence.
P(E) = n(E) / n(S) = 3 / 36 = 1 / 12
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c) All possible ouctcomes, E = S, give a sum less than 13, hence.
P(E) = n(E) / n(S) = 36 / 36 = 1
Question 5:
A die is rolled and a coin is tossed, find the probability that the die shows
an odd number and the coin shows a head.
Solution to Question 5:
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The sample space S of the experiment described in question 5 is as follows
S = { (1,H),(2,H),(3,H),(4,H),(5,H),(6,H)
(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)}
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Let E be the event "the die shows an odd number and the coin shows a head".
Event E may be described as follows
E={(1,H),(3,H),(5,H)}
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The probability P(E) is given by
P(E) = n(E) / n(S) = 3 / 12 = 1 / 4
Question 6:
A card is drawn at random from a deck of cards. Find the probability of
getting the 3 of diamond.
Solution to Question 6: