10/12/09
Oregon State University PH 201, Lecture #7
A ladybug is standing on the surface of a disk at a distance
of 20.0 cm from its center.
Initially the disk is rotating
clockwise so that the bug’s speed is 2.00 m/s.
Then the
disk undergoes a constant positive angular acceleration for
5.00 seconds.
The bug’s speed is then 8.00 m/s.
Find
:
The disk’s angular acceleration during the 5 seconds;
the disk’s angular displacement during the 5 seconds.
1.
±
= –6.00 rad/s
2
²³
= –125 rad
2.
±
= –0.600 rad/s
2
²³
= –12.5 rad
3.
±
= 1.00 rad/s
2
²³
= 7.50 rad
4.
±
= 10.0 rad/s
2
²³
= 75.0 rad
5.
None of the above.
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10/12/09
Oregon State University PH 201, Lecture #7
2Dimensional Motion (with Constant Acceleration)
The four equations of kinematics help us describe and calculate the
motion of any object undergoing constant acceleration (including
zero acceleration) with respect to any single axis.
But what if that object is moving relative to two axes at once?
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 Fall '08
 Staff
 Physics, Acceleration, Velocity, 2.00 m/s, 6.00 rad, 7.50 rad

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