Unformatted text preview: A ladybug is standing on the surface of a disk at a distance of 20.0 cm from its center. Initially the disk is rotating clockwise so that the bug’s speed is 2.00 m/s. Then the disk undergoes a constant positive angular acceleration for 5.00 seconds. The bug’s speed is then 8.00 m/s. Find: The disk’s angular acceleration during the 5 seconds; the disk’s angular displacement during the 5 seconds. 1. 2. 3. 4. = –6.00 rad/s2 = –0.600 rad/s2 = 1.00 rad/s2 = 10.0 rad/s2 = –125 rad = –1...
View
Full
Document
This note was uploaded on 01/13/2010 for the course PH 201 taught by Professor Staff during the Fall '08 term at Oregon State.
 Fall '08
 Staff
 Physics, Acceleration

Click to edit the document details