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Unformatted text preview: VIII. AP Physics C Problem Types and Hints 1988-1997 Yr. # Method for each part [Hint] Problem Type 88M1 Circ. Mot. Σ F=ma, vector [a is horiz], [too fast, so F f is downhill], F f = μ F N Banked Turn 88M2 k=F s /d (slope of graph), ∆ KE= ∫ Fdx (area of graph), area, ½mv 2 =area, slope=total k Graphical work, energy 88M3 I=kmr 2 , a 1 =a 2 and a=r α , Στ =I α (larger), Στ =I α (smaller), ϖ = ϖ o + α t, RKE=½I ϖ 2 Rotation of two objects 88E1 V=q/4 πε o r, Gauss, sphere, V= ∫ Edr, C=Q/V Gaussian E and V, Capacitance 88E2 Kirchoff or series and parallel, V C =V 4 Ω , C=Q/V, New Kirchoff, P=IV as fraction of total Circuit 88E3 Ampere’s Law Solenoid, Faraday: ε =–d Φ /dt, Faraday: ∫ Edl=–d Φ /dt , [B only to r 1 ] Ampere’s, Faraday’s Laws 89M1 energy, Σ F: Circle, gravity, circle, projectile kinematics or energy with v=v H , energy Energy, circle 89M2 Σ F A =ma, Στ pulley =I α , Σ F B =ma, Σ F C =ma Multiple object Σ F, Στ 89M3 energy, ϖ = m / k , T=2 π / ϖ , v max is at equilibrium: mg=kx, energy, (e) = (d) – (c ) spring energy, SHM 89E1 Gauss [q enclosed = 0], V= ∫ E • dr in from ∞ , Gauss, V= ∫ E • dr in from ∞ Gauss E and V 89E2 I = ε /R, where ε =–d Φ /dt, where Φ =B[h(vt)], F=I B, directions by Lenz’s Law Motional emf 89E3 U c =½QV, C=Q/V, C= ε o A/d, where d quadruples, energy, net V = IR, ∆ Q=Q o- Q equilibrium, E=VQ RC 90M1 Σ F A =ma, graph e-t/τ , graph (1- e-t/τ ), e-t/τ calculus graph, F=-kv motion 90M2 ½mv 2 =mgH, ½mv 2 =mgH+F f d, ½mv 2 + ½I ϖ 2 =mgH, ½mv 2 + ½I ϖ 2 =mgH + ½I ϖ 2 rotation on a ramp (energy) 90M3 [Find equil. position] mg-kx=0, ϖ = m / k , [separate when F N = 0] , a max = ϖ 2 A, v max = ϖ A SHM force, multiple object 90E1 Gaussian sphere: in insulator, in free space, in conductor [E=0], surface charge density...
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This note was uploaded on 01/13/2010 for the course PHYS 2425 taught by Professor Padhikari during the Spring '09 term at Richland Community College.
- Spring '09