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Unformatted text preview: EGM 3400 and 3401 (circle one) Spring 2007 Quiz 3 Open book/Closed notes – Time limit = 25 minutes A single wire ABC of length 2 m passes through the ring at C that is attached to a sphere which revolves at a constant speed v in the horizontal circle shown. Knowing that θ1 = 60o and θ 2 = 30o and the tension is the same in both portions of the wire, determine the speed v. (The figure is not drawn to scale. Imagine the sphere is small so that all of its mass is at C.) NAME:_______________________ L1 sin ( 60o ) = L2 sin ( 30o ) ⇒ L2 = L1 3 L1 + L2 = L1 1 + 3 = 2m ⇒ L1 = ⇒ ρ = L1 sin ( 60o ) = 3 1+ 3 m ( ) 2 m 1+ 3 ∑F y = T cos ( 60o ) + T cos ( 30o ) − mg = 0 v2 ∑ Fn = T sin ( 60o ) + T sin ( 30o ) = m
⇒v= 3 1+ 3 m ⋅ 9.81 m m = 2.494 2 s s ρ = mg ...
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This note was uploaded on 01/13/2010 for the course EGM 3401 taught by Professor Carlcrane during the Spring '08 term at University of Florida.
 Spring '08
 CARLCRANE
 Dynamics

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