Answers to Homework 9

Answers to Homework 9 - Answers to Homework 9 Pg 335 - 338...

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Answers to Homework 9 Pg 335 - 338 , #3, 4, 6, 10, 15, 16, 18, 21, and 23 3. The size of the two samples influences the magnitude of the estimated standard error in the denominator of the t-statistic. As sample size increases, the value of t also increases (moves farther from zero), and the likelihood of rejecting the null also increases. 4. The variability of the scores influences the estimated standard error in the denominator. As the variability of the scores increases, the value of t decreases (becomes closer to 0), and the likelihood of rejecting the null decreases. 6. a) s 2 = SS/(n-1) Group 1: 48/4-1 = 16 Group 2: 42/4-1 = 14 Pooled variance = SS1 + SS2 / df1 + df2 = 48+42 / 3+3 = 90/6 = 15 b) s 2 = SS/(n-1) Group 1: 48/4-1 = 16 Group 2: 42/8-1 = 6 Pooled variance = SS1 + SS2 / df1 + df2 = 48+42 / 3+7 = 90/10 = 9 10. a) SS1 + SS2 / df1 + df2 = 100 + 140 / 3+7 = 240/10 = 24 b) Estimated Standard Error = √(sp/n1) + (sp/n2) = √(24/4)+(24/8) = √6+3 = 3 c) A mean difference of 6 produces t = 6/3 = 2. With df of 10, the critical values is
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Answers to Homework 9 - Answers to Homework 9 Pg 335 - 338...

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